What is the integral from 0 to 1 of 2sin(x) ?

The integral from 0 to 1 of 2sin(x) is 2(-cos(1)+1)

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integral from 0 to 1 of 2sin(x)

\int_{0}^{1} 2 sin (x) d x

2 (- cos (1) + 1)

Decimal

0.91939 \dots

Solution steps

\int_{0}^{1} 2 sin (x) d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{1} sin (x) d x

Use the common integral:

\int sin (x) d x = - cos (x)

= 2 [- cos (x)]_{0}^{1}

Compute the boundaries:

- cos (1) + 1

= 2 (- cos (1) + 1)

What is the integral from 0 to 1 of 2sin(x) ?
The integral from 0 to 1 of 2sin(x) is 2(-cos(1)+1)