What is the integral from-infinity to 2 of θe^θ ?

The integral from-infinity to 2 of θe^θ is e^2

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integral from-infinity to 2 of θe^θ

\int_{- \infty}^{2} θ e^{θ} d θ

e^{2}

Decimal

7.38905 \dots

Solution steps

\int_{- \infty}^{2} θ e^{θ} d θ

Compute the indefinite integral:

\int θ e^{θ} d θ = e^{θ} θ - e^{θ} + C

Compute the boundaries:

\int_{- \infty}^{2} θ e^{θ} d θ = e^{2} - 0

= e^{2} - 0

Simplify

= e^{2}

What is the integral from-infinity to 2 of θe^θ ?
The integral from-infinity to 2 of θe^θ is e^2