What is the integral from 1 to 2 of (x^{-3}) ?

The integral from 1 to 2 of (x^{-3}) is 3/8

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integral from 1 to 2 of (x^{-3})

\int_{1}^{2} (x^{- 3}) d x

\frac{3}{8}

Decimal

0.375

Solution steps

\int_{1}^{2} x^{- 3} d x

Apply the Power Rule

= [- \frac{1}{2 x ^{2}}]_{1}^{2}

Compute the boundaries:

\frac{3}{8}

= \frac{3}{8}

What is the integral from 1 to 2 of (x^{-3}) ?
The integral from 1 to 2 of (x^{-3}) is 3/8