What is the integral from 0 to 2 of-2x^2 ?

The integral from 0 to 2 of-2x^2 is -16/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 0 to 2 of-2x^2

\int_{0}^{2} - 2 x^{2} d x

- \frac{16}{3}

Decimal

- 5.33333 \dots

Solution steps

\int_{0}^{2} - 2 x^{2} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - 2 \cdot \int_{0}^{2} x^{2} d x

Apply the Power Rule

= - 2 [\frac{x ^{3}}{3}]_{0}^{2}

Compute the boundaries:

\frac{8}{3}

= - 2 \cdot \frac{8}{3}

Simplify

= - \frac{16}{3}

What is the integral from 0 to 2 of-2x^2 ?
The integral from 0 to 2 of-2x^2 is -16/3