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Popular Calculus >

integral from 0 to 4 of (3x^2-4)

Solution

\int_{0}^{4} (3 x^{2} - 4) d x

Solution

48

Solution steps

\int_{0}^{4} 3 x^{2} - 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 3 x^{2} d x - \int_{0}^{4} 4 d x

\int_{0}^{4} 3 x^{2} d x = 64

\int_{0}^{4} 4 d x = 16

= 64 - 16

Simplify

= 48

Graph

Popular Examples

integral from-2 to 0 of (3-x^2)

\int_{- 2}^{0} (3 - x^{2}) d x

integral from 0 to 20 of 0.3x

\int_{0}^{20} 0.3 x d x

integral from-9 to 0 of xsqrt(81-x^2)

\int_{- 9}^{0} x 81 - x^{2} d x

integral from 1 to t^2 of sqrt(s+1)

\int_{1}^{t^{2}} s + 1 d s

integral from 0 to 3/2 pi of xsin(2x)

\int_{0}^{\frac{3}{2} π} x sin (2 x) d x

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of (3x^2-4) ?
The integral from 0 to 4 of (3x^2-4) is 48