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Popular Calculus >

integral from 0 to 2 of-3x^2+6x

Solution

\int_{0}^{2} - 3 x^{2} + 6 x d x

Solution

4

Solution steps

\int_{0}^{2} - 3 x^{2} + 6 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{2} 3 x^{2} d x + \int_{0}^{2} 6 x d x

\int_{0}^{2} 3 x^{2} d x = 8

\int_{0}^{2} 6 x d x = 12

= - 8 + 12

Simplify

= 4

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 2 of-3x^2+6x ?
The integral from 0 to 2 of-3x^2+6x is 4