What is the integral from-2 to 2 of 1/(x+3) ?

The integral from-2 to 2 of 1/(x+3) is ln(5)

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integral from-2 to 2 of 1/(x+3)

\int_{- 2}^{2} \frac{1}{x + 3} d x

ln (5)

Decimal

1.60943 \dots

Solution steps

\int_{- 2}^{2} \frac{1}{x + 3} d x

Apply u-substitution

= \int_{1}^{5} \frac{1}{u} d u

Use the common integral:

\int \frac{1}{u} d u = ln (∣ u ∣)

= [ln ∣ u ∣]_{1}^{5}

Compute the boundaries:

ln (5)

= ln (5)

What is the integral from-2 to 2 of 1/(x+3) ?
The integral from-2 to 2 of 1/(x+3) is ln(5)