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Popular Calculus >

integral from-4 to 6 of |x+1|

Solution

\int_{- 4}^{6} ∣ x + 1 ∣ d x

Solution

29

Solution steps

\int_{- 4}^{6} ∣ x + 1 ∣ d x

Eliminate Absolutes

= \int_{- 4}^{- 1} - x - 1 d x + \int_{- 1}^{6} x + 1 d x

\int_{- 4}^{- 1} - x - 1 d x = \frac{9}{2}

\int_{- 1}^{6} x + 1 d x = \frac{49}{2}

= \frac{9}{2} + \frac{49}{2}

Simplify

\frac{9}{2} + \frac{49}{2} : 29

= 29

Graph

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Frequently Asked Questions (FAQ)

What is the integral from-4 to 6 of |x+1| ?
The integral from-4 to 6 of |x+1| is 29