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Popular Calculus >

integral from 0 to 4 of 3x^2-x+1

Solution

\int_{0}^{4} 3 x^{2} - x + 1 d x

Solution

60

Solution steps

\int_{0}^{4} 3 x^{2} - x + 1 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 3 x^{2} d x - \int_{0}^{4} x d x + \int_{0}^{4} 1 d x

\int_{0}^{4} 3 x^{2} d x = 64

\int_{0}^{4} x d x = 8

\int_{0}^{4} 1 d x = 4

= 64 - 8 + 4

Simplify

= 60

Graph

Popular Examples

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\int_{0}^{2 π} z cos (n z) d z

integral from 0 to 1 of 10x^2

\int_{0}^{1} 10 x^{2} d x

integral from 0 to cos(θ) of 3r^2sin(θ)

\int_{0}^{c o s (θ)} 3 r^{2} sin (θ) d r

integral from-1 to 2 of 3x^2+5

\int_{- 1}^{2} 3 x^{2} + 5 d x

integral from 0 to 3 of sqrt(4-y)

\int_{0}^{3} 4 - y d y

Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of 3x^2-x+1 ?
The integral from 0 to 4 of 3x^2-x+1 is 60