integral from 2 to 1 of sin(x)

Lösung

\int_{2}^{1} sin (x) d x

cos (2) - cos (1)

Dezimale

- 0.95644 \dots

Schritte zur Lösung

\int_{2}^{1} sin (x) d x

\int_{a}^{b} f (x) d x = - \int_{b}^{a} f (x) d x, a < b

= - \int_{1}^{2} sin (x) d x

Nutze das gemeinsame Integral :

\int sin (x) d x = - cos (x)

= - [- cos (x)]_{1}^{2}

Berechne die Grenzen:

- cos (2) + cos (1)

= - (- cos (2) + cos (1))

Vereinfache

= cos (2) - cos (1)