What is the integral from 0 to 1.6 of g(x) ?

The integral from 0 to 1.6 of g(x) is g*1.28

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 0 to 1.6 of g(x)

\int_{0}^{1.6} g (x) d x

g \cdot 1.28

Solution steps

\int_{0}^{1.6} gx d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= g \cdot \int_{0}^{1.6} x d x

Apply the Power Rule

= g [\frac{x ^{2}}{2}]_{0}^{1.6}

Simplify

= g [0.5 x^{2}]_{0}^{1.6}

Compute the boundaries:

1.28

= g \cdot 1.28

What is the integral from 0 to 1.6 of g(x) ?
The integral from 0 to 1.6 of g(x) is g*1.28