integral from 0 to 3 of x^2cos(x)

Lösung

\int_{0}^{3} x^{2} cos (x) d x

7 sin (3) + 6 cos (3)

Dezimale

- 4.95211 \dots

Schritte zur Lösung

\int_{0}^{3} x^{2} cos (x) d x

Wende die partielle Integration an

= [x^{2} sin (x) - \int 2 x sin (x) d x]_{0}^{3}

\int 2 x sin (x) d x = 2 (- x cos (x) + sin (x))

= [x^{2} sin (x) - 2 (- x cos (x) + sin (x))]_{0}^{3}

Berechne die Grenzen:

7 sin (3) + 6 cos (3)

= 7 sin (3) + 6 cos (3)

\int_{0}^{1} x^{3} (x - \frac{1}{2}) d x

\int_{0}^{4} x (x - 2) (x - 4) d x

\int_{0}^{2} 2 t \cdot e^{t^{2}} d t

\int_{0}^{4} \frac{x}{x + 9} d x

\int_{0}^{10} \frac{5}{10 - x} d x