What is the integral from-3 to 4 of x-x^2+12 ?

The integral from-3 to 4 of x-x^2+12 is 343/6

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integral from-3 to 4 of x-x^2+12

\int_{- 3}^{4} x - x^{2} + 12 d x

\frac{343}{6}

Decimal

57.16666 \dots

Solution steps

\int_{- 3}^{4} x - x^{2} + 12 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 3}^{4} x d x - \int_{- 3}^{4} x^{2} d x + \int_{- 3}^{4} 12 d x

\int_{- 3}^{4} x d x = \frac{7}{2}

\int_{- 3}^{4} x^{2} d x = \frac{91}{3}

\int_{- 3}^{4} 12 d x = 84

= \frac{7}{2} - \frac{91}{3} + 84

Simplify

\frac{7}{2} - \frac{91}{3} + 84 : \frac{343}{6}

= \frac{343}{6}

What is the integral from-3 to 4 of x-x^2+12 ?
The integral from-3 to 4 of x-x^2+12 is 343/6