integral from 0 to 4 of 9+2sqrt(x)

Lösung

\int_{0}^{4} 9 + 2 x d x

\frac{140}{3}

Dezimale

46.66666 \dots

Schritte zur Lösung

\int_{0}^{4} 9 + 2 x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{4} 9 d x + \int_{0}^{4} 2 x d x

\int_{0}^{4} 9 d x = 36

\int_{0}^{4} 2 x d x = \frac{32}{3}

= 36 + \frac{32}{3}

Vereinfache

36 + \frac{32}{3} : \frac{140}{3}

= \frac{140}{3}

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