integral from 0 to 2 of (1+x)

Lösung

\int_{0}^{2} (1 + x) d x

4

Schritte zur Lösung

\int_{0}^{2} 1 + x d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} 1 d x + \int_{0}^{2} x d x

\int_{0}^{2} 1 d x = 2

\int_{0}^{2} x d x = 2

= 2 + 2

Vereinfache

= 4

\int_{0}^{x} (4 - x^{2}) d x

\int_{0}^{1} y^{3} e^{- y^{2}} d y

\int_{0}^{1} \frac{x}{4 + 5 x} d x

\int_{\frac{π}{2}}^{2 π} \frac{1}{2} x d x

\int_{0}^{3} \frac{1}{x ( 1 + x )} d x