integral from 1 to 3 of ((x^3-1))/(x^4)

Lösung

\int_{1}^{3} \frac{( x ^{3} - 1 )}{x ^{4}} d x

ln (3) - \frac{26}{81}

Dezimale

0.77762 \dots

Schritte zur Lösung

\int_{1}^{3} \frac{x ^{3} - 1}{x ^{4}} d x

Multipliziere aus

\frac{x ^{3} - 1}{x ^{4}} : \frac{1}{x} - \frac{1}{x ^{4}}

= \int_{1}^{3} \frac{1}{x} - \frac{1}{x ^{4}} d x

Wende die Summenregel an:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{3} \frac{1}{x} d x - \int_{1}^{3} \frac{1}{x ^{4}} d x

\int_{1}^{3} \frac{1}{x} d x = ln (3)

\int_{1}^{3} \frac{1}{x ^{4}} d x = \frac{26}{81}

= ln (3) - \frac{26}{81}

\int_{1}^{2} ρ^{2} d ρ

\int_{- 2}^{2} x^{2} - 3 d x

\int_{1}^{3} \frac{1}{x ^{6}} d x

\int_{1}^{4} (\frac{3}{x ^{2}}) d x

\int_{3}^{2} 2 x d x