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Popular Calculus >

integral from-1 to 1 of x+y+z

Solution

\int_{- 1}^{1} x + y + z d x

Solution

2 y + 2 z

Solution steps

\int_{- 1}^{1} x + y + z d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} y d x + \int_{- 1}^{1} z d x + \int_{- 1}^{1} x d x

\int_{- 1}^{1} y d x = 2 y

\int_{- 1}^{1} z d x = 2 z

\int_{- 1}^{1} x d x = 0

= 2 y + 2 z + 0

Simplify

= 2 y + 2 z

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Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of x+y+z ?
The integral from-1 to 1 of x+y+z is 2y+2z