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Popular Calculus >

integral from 0 to 4 of-x^2+4

Solution

\int_{0}^{4} - x^{2} + 4 d x

Solution

- \frac{16}{3}

+1

Decimal

- 5.33333 \dots

Solution steps

\int_{0}^{4} - x^{2} + 4 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= - \int_{0}^{4} x^{2} d x + \int_{0}^{4} 4 d x

\int_{0}^{4} x^{2} d x = \frac{64}{3}

\int_{0}^{4} 4 d x = 16

= - \frac{64}{3} + 16

Simplify

- \frac{64}{3} + 16 : - \frac{16}{3}

= - \frac{16}{3}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 4 of-x^2+4 ?
The integral from 0 to 4 of-x^2+4 is -16/3