What is the integral from-32 to 32 of \sqrt[5]{x^2} ?

The integral from-32 to 32 of \sqrt[5]{x^2} is 1280/7

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integral from-32 to 32 of \sqrt[5]{x^2}

\frac{1280}{7}

Decimal

182.85714 \dots

Solution steps

assuming

x \geq 0

= \int_{- 32}^{32} x^{\frac{2}{5}} d x

Apply the Power Rule

= [\frac{5}{7} x^{\frac{7}{5}}]_{- 32}^{32}

Compute the boundaries:

\frac{1280}{7}

= \frac{1280}{7}

What is the integral from-32 to 32 of \sqrt[5]{x^2} ?
The integral from-32 to 32 of \sqrt[5]{x^2} is 1280/7