What is the integral from 1 to 8 of f(t) ?

The integral from 1 to 8 of f(t) is (63f)/2

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 1 to 8 of f(t)

\int_{1}^{8} f (t) d t

\frac{63 f}{2}

Solution steps

\int_{1}^{8} f t d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= f \cdot \int_{1}^{8} t d t

Apply the Power Rule

= f [\frac{t ^{2}}{2}]_{1}^{8}

Compute the boundaries:

\frac{63}{2}

= f \frac{63}{2}

Simplify

= \frac{63 f}{2}

What is the integral from 1 to 8 of f(t) ?
The integral from 1 to 8 of f(t) is (63f)/2