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Popular Calculus >

integral from 1 to 2 of (1-x/2)

Solution

\int_{1}^{2} (1 - \frac{x}{2}) d x

Solution

\frac{1}{4}

+1

Decimal

0.25

Solution steps

\int_{1}^{2} 1 - \frac{x}{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} 1 d x - \int_{1}^{2} \frac{x}{2} d x

\int_{1}^{2} 1 d x = 1

\int_{1}^{2} \frac{x}{2} d x = \frac{3}{4}

= 1 - \frac{3}{4}

Simplify

1 - \frac{3}{4} : \frac{1}{4}

= \frac{1}{4}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 1 to 2 of (1-x/2) ?
The integral from 1 to 2 of (1-x/2) is 1/4