What is the integral from-1 to 1 of (x^2-x)(x+1) ?

The integral from-1 to 1 of (x^2-x)(x+1) is 0

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from-1 to 1 of (x^2-x)(x+1)

\int_{- 1}^{1} (x^{2} - x) (x + 1) d x

0

Solution steps

\int_{- 1}^{1} (x^{2} - x) (x + 1) d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

(x^{2} - x) (x + 1) :

Odd

= 0

What is the integral from-1 to 1 of (x^2-x)(x+1) ?
The integral from-1 to 1 of (x^2-x)(x+1) is 0