What is the integral from 0 to 0.8 of 48000x-21600 ?

The integral from 0 to 0.8 of 48000x-21600 is -1920

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integral from 0 to 0.8 of 48000x-21600

\int_{0}^{0.8} 48000 x - 21600 d x

- 1920

Solution steps

\int_{0}^{0.8} 48000 x - 21600 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{0.8} 48000 x d x - \int_{0}^{0.8} 21600 d x

\int_{0}^{0.8} 48000 x d x = 15360

\int_{0}^{0.8} 21600 d x = 17280

= 15360 - 17280

Simplify

= - 1920

What is the integral from 0 to 0.8 of 48000x-21600 ?
The integral from 0 to 0.8 of 48000x-21600 is -1920