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人気のある微分積分 >

integral from 2 to 3 of 95+1200t^2-20t

解

\int_{2}^{3} 95 + 1200 t^{2} - 20 t d t

解

7645

解答ステップ

\int_{2}^{3} 95 + 1200 t^{2} - 20 t d t

総和規則を適用する:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{2}^{3} 95 d t + \int_{2}^{3} 1200 t^{2} d t - \int_{2}^{3} 20 t d t

\int_{2}^{3} 95 d t = 95

\int_{2}^{3} 1200 t^{2} d t = 7600

\int_{2}^{3} 20 t d t = 50

= 95 + 7600 - 50

簡素化

= 7645

グラフ

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