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Popular Calculus >

integral from-1 to 1 of (8-x)

Solution

\int_{- 1}^{1} (8 - x) d x

Solution

16

Solution steps

\int_{- 1}^{1} 8 - x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{1} 8 d x - \int_{- 1}^{1} x d x

\int_{- 1}^{1} 8 d x = 16

\int_{- 1}^{1} x d x = 0

= 16 - 0

Simplify

= 16

Graph

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Frequently Asked Questions (FAQ)

What is the integral from-1 to 1 of (8-x) ?
The integral from-1 to 1 of (8-x) is 16