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Popular Calculus >

integral from 1 to 4 of x^2+3x+2

Solution

\int_{1}^{4} x^{2} + 3 x + 2 d x

Solution

\frac{99}{2}

+1

Decimal

49.5

Solution steps

\int_{1}^{4} x^{2} + 3 x + 2 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{4} x^{2} d x + \int_{1}^{4} 3 x d x + \int_{1}^{4} 2 d x

\int_{1}^{4} x^{2} d x = 21

\int_{1}^{4} 3 x d x = \frac{45}{2}

\int_{1}^{4} 2 d x = 6

= 21 + \frac{45}{2} + 6

Simplify

21 + \frac{45}{2} + 6 : \frac{99}{2}

= \frac{99}{2}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 1 to 4 of x^2+3x+2 ?
The integral from 1 to 4 of x^2+3x+2 is 99/2