What is the integral from 0 to 2 of 1/((x+2)^4) ?

The integral from 0 to 2 of 1/((x+2)^4) is 7/192

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 0 to 2 of 1/((x+2)^4)

\int_{0}^{2} \frac{1}{( x + 2 ) ^{4}} d x

\frac{7}{192}

Decimal

0.03645 \dots

Solution steps

\int_{0}^{2} \frac{1}{( x + 2 ) ^{4}} d x

Apply u-substitution

= \int_{2}^{4} \frac{1}{u ^{4}} d u

Apply the Power Rule

= [- \frac{1}{3 u ^{3}}]_{2}^{4}

Compute the boundaries:

\frac{7}{192}

= \frac{7}{192}

What is the integral from 0 to 2 of 1/((x+2)^4) ?
The integral from 0 to 2 of 1/((x+2)^4) is 7/192