What is the integral from 0 to 8 of (\sqrt[3]{x})^2 ?

The integral from 0 to 8 of (\sqrt[3]{x})^2 is 96/5

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integral from 0 to 8 of (\sqrt[3]{x})^2

\frac{96}{5}

Decimal

19.2

Solution steps

Apply Integration By Parts

\int \frac{2}{3} x^{\frac{2}{3}} d x = \frac{2}{5} x^{\frac{5}{3}}

Simplify

= [\frac{3}{5} x^{\frac{5}{3}}]_{0}^{8}

Compute the boundaries:

\frac{96}{5}

= \frac{96}{5}

What is the integral from 0 to 8 of (\sqrt[3]{x})^2 ?
The integral from 0 to 8 of (\sqrt[3]{x})^2 is 96/5