What is the integral from 4 to 10 of g(t) ?

The integral from 4 to 10 of g(t) is g*42

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integral from 4 to 10 of g(t)

\int_{4}^{10} g (t) d t

g \cdot 42

Solution steps

\int_{4}^{10} g t d t

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= g \cdot \int_{4}^{10} t d t

Apply the Power Rule

= g [\frac{t ^{2}}{2}]_{4}^{10}

Compute the boundaries:

42

= g \cdot 42

What is the integral from 4 to 10 of g(t) ?
The integral from 4 to 10 of g(t) is g*42