What is the integral from-4 to 3 of 3x^2+3x-36 ?

The integral from-4 to 3 of 3x^2+3x-36 is -343/2

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integral from-4 to 3 of 3x^2+3x-36

\int_{- 4}^{3} 3 x^{2} + 3 x - 36 d x

- \frac{343}{2}

Decimal

- 171.5

Solution steps

\int_{- 4}^{3} 3 x^{2} + 3 x - 36 d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 4}^{3} 3 x^{2} d x + \int_{- 4}^{3} 3 x d x - \int_{- 4}^{3} 36 d x

\int_{- 4}^{3} 3 x^{2} d x = 91

\int_{- 4}^{3} 3 x d x = - \frac{21}{2}

\int_{- 4}^{3} 36 d x = 252

= 91 - \frac{21}{2} - 252

Simplify

91 - \frac{21}{2} - 252 : - \frac{343}{2}

= - \frac{343}{2}

What is the integral from-4 to 3 of 3x^2+3x-36 ?
The integral from-4 to 3 of 3x^2+3x-36 is -343/2