What is the integral from 0 to 2 of (x^2-1+2x) ?

The integral from 0 to 2 of (x^2-1+2x) is 14/3

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integral from 0 to 2 of (x^2-1+2x)

\int_{0}^{2} (x^{2} - 1 + 2 x) d x

\frac{14}{3}

Decimal

4.66666 \dots

Solution steps

\int_{0}^{2} x^{2} - 1 + 2 x d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{2} x^{2} d x - \int_{0}^{2} 1 d x + \int_{0}^{2} 2 x d x

\int_{0}^{2} x^{2} d x = \frac{8}{3}

\int_{0}^{2} 1 d x = 2

\int_{0}^{2} 2 x d x = 4

= \frac{8}{3} - 2 + 4

Simplify

\frac{8}{3} - 2 + 4 : \frac{14}{3}

= \frac{14}{3}

What is the integral from 0 to 2 of (x^2-1+2x) ?
The integral from 0 to 2 of (x^2-1+2x) is 14/3