What is the integral from 1 to 2 of (x^3-x^2) ?

The integral from 1 to 2 of (x^3-x^2) is 17/12

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integral from 1 to 2 of (x^3-x^2)

\int_{1}^{2} (x^{3} - x^{2}) d x

\frac{17}{12}

Decimal

1.41666 \dots

Solution steps

\int_{1}^{2} x^{3} - x^{2} d x

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{2} x^{3} d x - \int_{1}^{2} x^{2} d x

\int_{1}^{2} x^{3} d x = \frac{15}{4}

\int_{1}^{2} x^{2} d x = \frac{7}{3}

= \frac{15}{4} - \frac{7}{3}

Simplify

\frac{15}{4} - \frac{7}{3} : \frac{17}{12}

= \frac{17}{12}

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What is the integral from 1 to 2 of (x^3-x^2) ?
The integral from 1 to 2 of (x^3-x^2) is 17/12