What is the integral from-4 to 4 of x^3-16x ?

The integral from-4 to 4 of x^3-16x is 0

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integral from-4 to 4 of x^3-16x

\int_{- 4}^{4} x^{3} - 16 x d x

0

Solution steps

\int_{- 4}^{4} x^{3} - 16 x d x

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

x^{3} - 16 x :

Odd

= 0

\int_{1}^{2} x^{3} - x^{2} d x

\int_{- 2}^{1} x + 2 d x

\int_{1}^{\infty} x \cdot \frac{4}{x ^{5}} d x

\int_{1}^{3} \frac{( x ^{2} + 5 )}{x} d x

\int_{4}^{7} x ln (ln (x)) d x

What is the integral from-4 to 4 of x^3-16x ?
The integral from-4 to 4 of x^3-16x is 0