What is the integral from 0 to sqrt(y of)e^{-x} ?

The integral from 0 to sqrt(y of)e^{-x} is -e^{-sqrt(y)}+1

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integral from 0 to sqrt(y of)e^{-x}

\int_{0}^{y} e^{- x} d x

- e^{- y} + 1

Solution steps

\int_{0}^{y} e^{- x} d x

Apply u-substitution

= \int_{0}^{- y} - e^{u} d u

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= - \int_{0}^{- y} e^{u} d u

Use the common integral:

\int e^{u} d u = e^{u}

= - [e^{u}]_{0}^{- y}

Compute the boundaries:

e^{- y} - 1

= - (e^{- y} - 1)

Simplify

= - e^{- y} + 1

What is the integral from 0 to sqrt(y of)e^{-x} ?
The integral from 0 to sqrt(y of)e^{-x} is -e^{-sqrt(y)}+1