What is the integral from-1 to 1 of (y^3)/3+2y^3 ?

The integral from-1 to 1 of (y^3)/3+2y^3 is 0

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integral from-1 to 1 of (y^3)/3+2y^3

\int_{- 1}^{1} \frac{y ^{3}}{3} + 2 y^{3} d y

0

Solution steps

\int_{- 1}^{1} \frac{y ^{3}}{3} + 2 y^{3} d y

If f(x) is an odd function and continuous at:

[- a, a]

then

\int_{- a}^{a} f (x) d x = 0

Parity of

\frac{y ^{3}}{3} + 2 y^{3} :

Odd

= 0

\int_{2}^{3} (\frac{1}{x - 1} + x) d x

\int_{6}^{5} (sin (x)) d x

\int_{2}^{8} - \frac{6}{x} d x

\int_{0}^{y} (1 - x y) d x

\int_{1}^{2} (0.5 - 0.125 x) d x

What is the integral from-1 to 1 of (y^3)/3+2y^3 ?
The integral from-1 to 1 of (y^3)/3+2y^3 is 0