What is the integral from 1 to 5 of t^2-2t-15 ?

The integral from 1 to 5 of t^2-2t-15 is -128/3

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

integral from 1 to 5 of t^2-2t-15

\int_{1}^{5} t^{2} - 2 t - 15 d t

- \frac{128}{3}

Decimal

- 42.66666 \dots

Solution steps

\int_{1}^{5} t^{2} - 2 t - 15 d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{1}^{5} t^{2} d t - \int_{1}^{5} 2 t d t - \int_{1}^{5} 15 d t

\int_{1}^{5} t^{2} d t = \frac{124}{3}

\int_{1}^{5} 2 t d t = 24

\int_{1}^{5} 15 d t = 60

= \frac{124}{3} - 24 - 60

Simplify

\frac{124}{3} - 24 - 60 : - \frac{128}{3}

= - \frac{128}{3}

What is the integral from 1 to 5 of t^2-2t-15 ?
The integral from 1 to 5 of t^2-2t-15 is -128/3