What is the integral from 1 to x of e^t ?

The integral from 1 to x of e^t is e^x-e

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integral from 1 to x of e^t

\int_{1}^{x} e^{t} d t

e^{x} - e

Solution steps

\int_{1}^{x} e^{t} d t

Use the common integral:

\int e^{t} d t = e^{t}

= [e^{t}]_{1}^{x}

Compute the boundaries:

e^{x} - e

= e^{x} - e

\int_{0}^{2} \frac{2 x}{2 + x ^{2}} d x

\int_{0}^{2} x^{3} (2 - x) d x

\int_{e}^{\infty} \frac{1}{x} d x

\int_{0}^{3 t} \frac{sin ( u )}{u} d u

\int_{0}^{\infty} x \cdot e^{x} d x

What is the integral from 1 to x of e^t ?
The integral from 1 to x of e^t is e^x-e