What is the derivative of x^3-3x^2-8x+2 ?

The derivative of x^3-3x^2-8x+2 is 3x^2-6x-8

What is the first derivative of x^3-3x^2-8x+2 ?

The first derivative of x^3-3x^2-8x+2 is 3x^2-6x-8

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\frac{d}{d x} (x^{3} - 3 x^{2} - 8 x + 2)

3 x^{2} - 6 x - 8

Solution steps

\frac{d}{d x} (x^{3} - 3 x^{2} - 8 x + 2)

Apply the Sum/Difference Rule:

(f \pm g)^{'} = f^{'} \pm g^{'}

= \frac{d}{d x} (x^{3}) - \frac{d}{d x} (3 x^{2}) - \frac{d}{d x} (8 x) + \frac{d}{d x} (2)

\frac{d}{d x} (x^{3}) = 3 x^{2}

\frac{d}{d x} (3 x^{2}) = 6 x

\frac{d}{d x} (8 x) = 8

\frac{d}{d x} (2) = 0

= 3 x^{2} - 6 x - 8 + 0

Simplify

= 3 x^{2} - 6 x - 8

What is the derivative of x^3-3x^2-8x+2 ?
The derivative of x^3-3x^2-8x+2 is 3x^2-6x-8
What is the first derivative of x^3-3x^2-8x+2 ?
The first derivative of x^3-3x^2-8x+2 is 3x^2-6x-8