What is the integral from 1 to sqrt(3 of) 3/(1+x^2) ?

The integral from 1 to sqrt(3 of) 3/(1+x^2) is pi/4

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integral from 1 to sqrt(3 of) 3/(1+x^2)

\int_{1}^{3} \frac{3}{1 + x ^{2}} d x

\frac{π}{4}

Decimal

0.78539 \dots

Solution steps

\int_{1}^{3} \frac{3}{1 + x ^{2}} d x

Take the constant out:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{1}^{3} \frac{1}{1 + x ^{2}} d x

Use the common integral:

\int \frac{1}{1 + x ^{2}} d x = arctan (x)

= 3 [arctan (x)]_{1}^{3}

Compute the boundaries:

\frac{π}{12}

= 3 \cdot \frac{π}{12}

Simplify

= \frac{π}{4}

What is the integral from 1 to sqrt(3 of) 3/(1+x^2) ?
The integral from 1 to sqrt(3 of) 3/(1+x^2) is pi/4