integral from 0 to pi/2 of tsin(t)

Lösung

\int_{0}^{\frac{π}{2}} t sin (t) d t

1

Schritte zur Lösung

\int_{0}^{\frac{π}{2}} t sin (t) d t

Wende die partielle Integration an

= [- t cos (t) - \int - cos (t) d t]_{0}^{\frac{π}{2}}

\int - cos (t) d t = - sin (t)

= [- t cos (t) - (- sin (t))]_{0}^{\frac{π}{2}}

Vereinfache

= [- t cos (t) + sin (t)]_{0}^{\frac{π}{2}}

Berechne die Grenzen:

1

= 1

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