integral from 0 to 2 of (3t-1)^{60}

Lösung

\int_{0}^{2} (3 t - 1)^{60} d t

\frac{5 ^{61} + 1}{183}

Dezimale

2.36984 E 40

Schritte zur Lösung

\int_{0}^{2} (3 t - 1)^{60} d t

Wende U-Substitution an

= \int_{- 1}^{5} \frac{u ^{60}}{3} d u

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= \frac{1}{3} \cdot \int_{- 1}^{5} u^{60} d u

Wende die Potenzregel an

= \frac{1}{3} [\frac{u ^{61}}{61}]_{- 1}^{5}

Berechne die Grenzen:

\frac{5 ^{61}}{61} + \frac{1}{61}

= \frac{1}{3} (\frac{5 ^{61}}{61} + \frac{1}{61})

Vereinfache

= \frac{5 ^{61} + 1}{183}

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