integral from 0 to 16 of (2sqrt(x))

Lösung

\int_{0}^{16} (2 x) d x

\frac{256}{3}

Dezimale

85.33333 \dots

Schritte zur Lösung

\int_{0}^{16} 2 x d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 2 \cdot \int_{0}^{16} x d x

Wende die Potenzregel an

= 2 [\frac{2}{3} x^{\frac{3}{2}}]_{0}^{16}

Berechne die Grenzen:

\frac{128}{3}

= 2 \cdot \frac{128}{3}

Vereinfache

= \frac{256}{3}

\int_{3}^{4} (t^{2} - 2 t - 3) d t

\int_{1}^{2} \frac{x}{1 + x ^{2}} d x

\int_{x}^{y} e^{t^{2}} d t

\int_{0}^{x} t f (x - t) d t

\int_{0}^{\frac{π}{3}} sin (t) d t