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Popular Calculus >

integral from 0 to 3 of (t^2-2t)

Solution

\int_{0}^{3} (t^{2} - 2 t) d t

Solution

0

Solution steps

\int_{0}^{3} t^{2} - 2 t d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{3} t^{2} d t - \int_{0}^{3} 2 t d t

\int_{0}^{3} t^{2} d t = 9

\int_{0}^{3} 2 t d t = 9

= 9 - 9

Simplify

= 0

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 3 of (t^2-2t) ?
The integral from 0 to 3 of (t^2-2t) is 0