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Popular Calculus >

integral from 0 to 1 of t^2-t

Solution

\int_{0}^{1} t^{2} - t d t

Solution

- \frac{1}{6}

+1

Decimal

- 0.16666 \dots

Solution steps

\int_{0}^{1} t^{2} - t d t

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{0}^{1} t^{2} d t - \int_{0}^{1} t d t

\int_{0}^{1} t^{2} d t = \frac{1}{3}

\int_{0}^{1} t d t = \frac{1}{2}

= \frac{1}{3} - \frac{1}{2}

Simplify

\frac{1}{3} - \frac{1}{2} : - \frac{1}{6}

= - \frac{1}{6}

Graph

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Frequently Asked Questions (FAQ)

What is the integral from 0 to 1 of t^2-t ?
The integral from 0 to 1 of t^2-t is -1/6