What is the derivative of 30ln(2x+1) ?

The derivative of 30ln(2x+1) is (60)/(2x+1)

What is the first derivative of 30ln(2x+1) ?

The first derivative of 30ln(2x+1) is (60)/(2x+1)

English

Español

Português

Français

Deutsch

Italiano

Русский

中文(简体)

한국어

日本語

Tiếng Việt

עברית

العربية

derivative of

30 ln (2 x + 1)

\frac{60}{2 x + 1}

Solution steps

\frac{d}{d x} (30 ln (2 x + 1))

Take the constant out:

(a \cdot f)^{'} = a \cdot f^{'}

= 30 \frac{d}{d x} (ln (2 x + 1))

Apply the chain rule:

\frac{1}{2 x + 1} \frac{d}{d x} (2 x + 1)

= \frac{1}{2 x + 1} \frac{d}{d x} (2 x + 1)

\frac{d}{d x} (2 x + 1) = 2

= 30 \cdot \frac{1}{2 x + 1} \cdot 2

Simplify

30 \cdot \frac{1}{2 x + 1} \cdot 2 : \frac{60}{2 x + 1}

= \frac{60}{2 x + 1}

What is the derivative of 30ln(2x+1) ?
The derivative of 30ln(2x+1) is (60)/(2x+1)
What is the first derivative of 30ln(2x+1) ?
The first derivative of 30ln(2x+1) is (60)/(2x+1)