What is the integral from 0 to 4-y^2 of 1 ?

The integral from 0 to 4-y^2 of 1 is -y^2+4

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integral from 0 to 4-y^2 of 1

\int_{0}^{4 - y^{2}} 1

- y^{2} + 4

Solution steps

\int_{0}^{4 - y^{2}} 1 d y

Integral of a constant:

\int a d x = a x

= [1 \cdot y]_{0}^{4 - y^{2}}

Simplify

= [y]_{0}^{4 - y^{2}}

Compute the boundaries:

- y^{2} + 4

= - y^{2} + 4

What is the integral from 0 to 4-y^2 of 1 ?
The integral from 0 to 4-y^2 of 1 is -y^2+4