What is the integral from-1 to 2 of (2y^2-2y-4) ?

The integral from-1 to 2 of (2y^2-2y-4) is -9

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integral from-1 to 2 of (2y^2-2y-4)

\int_{- 1}^{2} (2 y^{2} - 2 y - 4) d y

- 9

Solution steps

\int_{- 1}^{2} 2 y^{2} - 2 y - 4 d y

Apply the Sum Rule:

\int f (x) \pm g (x) d x = \int f (x) d x \pm \int g (x) d x

= \int_{- 1}^{2} 2 y^{2} d y - \int_{- 1}^{2} 2 y d y - \int_{- 1}^{2} 4 d y

\int_{- 1}^{2} 2 y^{2} d y = 6

\int_{- 1}^{2} 2 y d y = 3

\int_{- 1}^{2} 4 d y = 12

= 6 - 3 - 12

Simplify

= - 9

What is the integral from-1 to 2 of (2y^2-2y-4) ?
The integral from-1 to 2 of (2y^2-2y-4) is -9