What is the integral from 3 to 9 of (1/(x^2)) ?

The integral from 3 to 9 of (1/(x^2)) is 2/9

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integral from 3 to 9 of (1/(x^2))

\int_{3}^{9} (\frac{1}{x ^{2}}) d x

\frac{2}{9}

Decimal

0.22222 \dots

Solution steps

\int_{3}^{9} \frac{1}{x ^{2}} d x

Apply the Power Rule

= [- \frac{1}{x}]_{3}^{9}

Compute the boundaries:

\frac{2}{9}

= \frac{2}{9}

What is the integral from 3 to 9 of (1/(x^2)) ?
The integral from 3 to 9 of (1/(x^2)) is 2/9