integral from 1 to 16 of 3/(sqrt(x))

Lösung

\int_{1}^{16} \frac{3}{x} d x

18

Schritte zur Lösung

\int_{1}^{16} \frac{3}{x} d x

Entferne die Konstante:

\int a \cdot f (x) d x = a \cdot \int f (x) d x

= 3 \cdot \int_{1}^{16} \frac{1}{x} d x

Wende die Potenzregel an

= 3 [2 x^{\frac{1}{2}}]_{1}^{16}

Wende Radikal Regel an:

a^{\frac{1}{n}} = n a

= 3 [2 x]_{1}^{16}

Berechne die Grenzen:

6

= 3 \cdot 6

Vereinfache

= 18

\int_{3}^{0} (6 x - x^{3}) d x

\int_{- 3}^{3} (9 x - x^{3}) (20 x) d x

\int_{0}^{\frac{π}{2}} 6 cos (x) d x

\int_{1}^{x^{2}} (t - 4) e^{- t^{2}} d t

\int_{0}^{6} (16 - 2 x)^{\frac{1}{2}} d x