What is the integral from 0 to x^4 of e^t ?

The integral from 0 to x^4 of e^t is e^{x^4}-1

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integral from 0 to x^4 of e^t

\int_{0}^{x^{4}} e^{t} d t

e^{x^{4}} - 1

Solution steps

\int_{0}^{x^{4}} e^{t} d t

Use the common integral:

\int e^{t} d t = e^{t}

= [e^{t}]_{0}^{x^{4}}

Compute the boundaries:

e^{x^{4}} - 1

= e^{x^{4}} - 1

\int_{3}^{4} x^{2} - 3 x d x

\int_{0}^{9} \frac{1}{( 1 + x ) ^{2}} d x

\int_{1}^{t} - 5 t + 9 d t

\int_{0}^{x} sin (t^{3} + 1) d t

\int_{1}^{2} (x + 3)^{5} d x

What is the integral from 0 to x^4 of e^t ?
The integral from 0 to x^4 of e^t is e^{x^4}-1